【 使用环境 】生产环境
【 OB or 4他组件 】
ob-operator
【 使用版本 】
operator 2.3.2 ob 4.2.5.3
【问题描述】清晰明确描述问题
cluster 资源配置如下:
tenant想给6C12G的资源报错MEMORY resource not enough,相关参数如下:
请教下各位大佬,请问这个可用资源是如何计算的
【 使用环境 】生产环境
【 OB or 4他组件 】
ob-operator
【 使用版本 】
operator 2.3.2 ob 4.2.5.3
【问题描述】清晰明确描述问题
cluster 资源配置如下:
请教下各位大佬,请问这个可用资源是如何计算的
16 x 1024M - 14745M = 1639M -1024M(system_memory)= 615M? 这部分是什么占用的。
14745M -2 x 1024M(SYS Tenant)-500M(memory_reserved) = 12197M < 12288M(12G) 是这么算的吗
show parameters where name in (‘memory_limit’,‘memory_limit_percentage’,‘system_memory’,‘log_disk_size’,‘log_disk_percentage’,‘datafile_size’,‘datafile_disk_percentage’);
select zone,concat(SVR_IP,’:’,SVR_PORT) observer,
cpu_capacity_max cpu_total,cpu_assigned_max cpu_assigned,
cpu_capacity-cpu_assigned_max as cpu_free,
round(memory_limit/1024/1024/1024,2) as memory_total,
round((memory_limit-mem_capacity)/1024/1024/1024,2) as system_memory,
round(mem_assigned/1024/1024/1024,2) as mem_assigned,
round((mem_capacity-mem_assigned)/1024/1024/1024,2) as memory_free,
round(log_disk_capacity/1024/1024/1024,2) as log_disk_capacity,
round(log_disk_assigned/1024/1024/1024,2) as log_disk_assigned,
round((log_disk_capacity-log_disk_assigned)/1024/1024/1024,2) as log_disk_free,
round((data_disk_capacity/1024/1024/1024),2) as data_disk,
round((data_disk_in_use/1024/1024/1024),2) as data_disk_used,
round((data_disk_capacity-data_disk_in_use)/1024/1024/1024,2) as data_disk_free
from oceanbase.gv$ob_servers;
select a.zone,a.svr_ip,b.tenant_name,b.tenant_type, a.max_cpu, a.min_cpu,
round(a.memory_size/1024/1024/1024,2) memory_size_gb,
round(a.log_disk_size/1024/1024/1024,2) log_disk_size,
round(a.log_disk_in_use/1024/1024/1024,2) log_disk_in_use,
round(a.data_disk_in_use/1024/1024/1024,2) data_disk_in_use
from oceanbase.gv$ob_units a join oceanbase.dba_ob_tenants b on a.tenant_id=b.tenant_id order by b.tenant_name;